How to Build a Clay Igloo (/How to Present Igloo Mathematically


 * Labeling of the Layers:


 * 1) The length should be the circumference of the layer's circle(X)
 * 2) Measure the Height that forms perpendicular with the dashed lines (Y)
 * 3) Solve the angle of the that specific angle of the ramp (theta)
 * Arctangent( Height / Base) = angle of the trapezoidal block (in degrees)


 * If the Igloo is built correctly:
 * The angle of the blocks in that particular layer should have an increasing trend from lowest to highest degrees
 * The Base is the radius of that specific radius; in other words, it should be the constant
 * Height should increase from lowest block to tallest block

What Not To Do
 * Presenting the Igloo into single equation:
 * y = -ax^2 + b; x = from a vertical point of view, the block number; b = height of the igloo
 * Problems Regarding Single Equation:
 * Inaccurate display = it doesn't necessarily show every single block in the 3-Dimensional plain
 * Symmetrically, the length of the block doesn't equal to each other side's block
 * Symmetrically, the height should be similar, if not the same, because of quadratic's concept. However, that's not true for the spiral igloo
 * Calculating the Volume:
 * Integrate 2pix(-ax^2 + b)dx [0, radius of one layer]
 * This doesn't answer the question...
 * Don't act smart by calculating unnecessary quantity or value if it doesn't calculate the shape of the block or the ramp of an igloo