Lhermite's models

Lhermite's models are interesting ways to synthesize various objects that are apparently scattered.

Prime numbers and the model of three arrows
$$\mathbb{U}_n=\sum_{i=1}^{f\left(n\right)}{\left(\left[\frac{1+\sum_{m=1}^{i}{\varphi\left(m\right)}}{n+1}\right]\times\left[\frac{n+1}{1+\sum_{m=1}^{i}{\varphi\left(m\right) }}\right]\times i\times\varphi\left(i\right)\right)}$$

$$\mathbb{U}_n=\sum_{i=1}^{f\left(n\right)}{\left(\left[\frac{\alpha+\sum_{m=1}^{i}{\varphi\left(m\right)}}{n+\alpha}\right]\times\left[\frac{n+\alpha}{\alpha+\sum_{m=1}^{i}{\varphi\left(m\right) }}\right]\times i\times\varphi\left(i\right)\right)}$$

with $$f\left(n\right)\geq \mathbb{U}_n  $$ and  $$ \alpha >0  $$


 * $$P_n = \sum_{i=1}^{2^{2^{n}}}\left(\left\lfloor\frac {1+ \sum_{m=1}^{i}{\left( 1-\left\lfloor{\frac{\left\lfloor{\frac{\left(m!\right)^2}{m^3}}\right\rfloor}{\frac{\left(m!\right)^2}{m^3}}}\right\rfloor\right)}}{n+1}\right\rfloor\times{\left\lfloor\frac{n+1}{1+ \sum_{m=1}^{i}{\left( 1-\left\lfloor{\frac{\left\lfloor{\frac{\left(m!\right)^2}{m^3}}\right\rfloor}{\frac{\left(m!\right)^2}{m^3}}}\right\rfloor\right)}}\right\rfloor}\times{i}\times{\left({1-\left\lfloor{\frac{\left\lfloor(\frac{\left(i!\right)^2}{i^3}\right\rfloor}{\frac{\left(i!\right)^2}{i^3}}}\right\rfloor}\right)}\right) $$


 * $$P_n = \sum_{i=1}^{2^n}\left(\left\lfloor\frac {1+ \sum_{m=1}^{i}{\left( 1-\left\lfloor{\frac{\left\lfloor{\frac{\left(m!\right)^2}{m^3}}\right\rfloor}{\frac{\left(m!\right)^2}{m^3}}}\right\rfloor\right)}}{n+1}\right\rfloor\times{\left\lfloor\frac{n+1}{1+ \sum_{m=1}^{i}{\left( 1-\left\lfloor{\frac{\left\lfloor{\frac{\left(m!\right)^2}{m^3}}\right\rfloor}{\frac{\left(m!\right)^2}{m^3}}}\right\rfloor\right)}}\right\rfloor}\times{i}\times{\left({1-\left\lfloor{\frac{\left\lfloor(\frac{\left(i!\right)^2}{i^3}\right\rfloor}{\frac{\left(i!\right)^2}{i^3}}}\right\rfloor}\right)}\right) $$


 * $$P_n = \sum_{i=1}^{1+n!}\left(\left\lfloor\frac {1+ \sum_{m=1}^{i}{\left( 1-\left\lfloor{\frac{\left\lfloor{\frac{\left(m!\right)^2}{m^3}}\right\rfloor}{\frac{\left(m!\right)^2}{m^3}}}\right\rfloor\right)}}{n+1}\right\rfloor\times{\left\lfloor\frac{n+1}{1+ \sum_{m=1}^{i}{\left( 1-\left\lfloor{\frac{\left\lfloor{\frac{\left(m!\right)^2}{m^3}}\right\rfloor}{\frac{\left(m!\right)^2}{m^3}}}\right\rfloor\right)}}\right\rfloor}\times{i}\times{\left({1-\left\lfloor{\frac{\left\lfloor(\frac{\left(i!\right)^2}{i^3}\right\rfloor}{\frac{\left(i!\right)^2}{i^3}}}\right\rfloor}\right)}\right) $$


 * $$P_n = \sum_{i=1}^{2^n}\left(\left[\frac {1+ \sum_{m=1}^{i}{\left( 1-\left[{\frac{\left[{\frac{\left(m!\right)^2}{m^3}}\right]}{\frac{\left(m!\right)^2}{m^3}}}\right]\right)}}{n+1}\right]\times{\left[\frac{n+1}{1+ \sum_{m=1}^{i}{\left( 1-\left[{\frac{\left[{\frac{\left(m!\right)^2}{m^3}}\right]}{\frac{\left(m!\right)^2}{m^3}}}\right]\right)}}\right]}\times{i}\times{\left({1-\left[{\frac{\left[(\frac{\left(i!\right)^2}{i^3}\right]}{\frac{\left(i!\right)^2}{i^3}}}\right]}\right)}\right) $$


 * $$P_n = \sum_{i=1}^{2^{2^{n}}

}\left(\left[\frac {1+ \sum_{m=1}^{i}{\left( 1-\left[{\frac{\left[{\frac{\left(m!\right)^2}{m^3}}\right]}{\frac{\left(m!\right)^2}{m^3}}}\right]\right)}}{n+1}\right]\times{\left[\frac{n+1}{1+ \sum_{m=1}^{i}{\left( 1-\left[{\frac{\left[{\frac{\left(m!\right)^2}{m^3}}\right]}{\frac{\left(m!\right)^2}{m^3}}}\right]\right)}}\right]}\times{i}\times{\left({1-\left[{\frac{\left[(\frac{\left(i!\right)^2}{i^3}\right]}{\frac{\left(i!\right)^2}{i^3}}}\right]}\right)}\right) $$

Red balls and blue balls and prime numbers
$$ P_{\left(\left(1-\left[\frac{\left[\frac{\left(n!\right)^2}{n^3}\right]}{\frac{\left(n!\right)^2}{n^3}}\right]\right)\times\left(\sum_{m=1}^{n}{\left(1-\left[\frac{\left[\frac{\left(m!\right)^2}{m^3}\right]}{\frac{\left(m!\right)^2}{m^3}}\right]\right)}-i\right)+i\right)}=\left(P_i-n\right)\times\left[\frac{\left[\frac{\left(n!\right)^2}{n^3}\right]}{\frac{\left(n!\right)^2}{n^3}}\right]+n$$

Prime numbers and the model of three arrows according to Wilson's theorem

 * $$\forall n \in \mathbb{N'} $$


 * $$(n-1)! \equiv\ -1 \pmod n \Leftrightarrow n \in \mathbb{P}$$

in the same way, it is advanced that


 * $$\forall n \in \mathbb{N'} $$


 * $$\left[ \frac{\left[\frac{\left(n-1\right)!+1}{n}\right]}{\frac{\left(n-1\right)!+1}{n}}\right]=1 \Leftrightarrow n \in \mathbb{P}$$

It's very evident that


 * $$\forall n \in \mathbb{N'} $$


 * $$\left[ \frac{\left[\frac{\left(n-1\right)!+1}{n}\right]}{\frac{\left(n-1\right)!+1}{n}}\right]=0 \Leftrightarrow n \notin \mathbb{P}$$

Therefore, according to Lhermite's models and Wilson's theorem, there are two evident theorems :


 * $$\forall n \in \mathbb{N^*} $$


 * $$\left[ \frac{\left[\frac{\left(n-1\right)!+1}{n}\right]}{\frac{\left(n-1\right)!+1}{n}}\right]-\left[\frac{1}{n}\right]=1 \Leftrightarrow n \in \mathbb{P}$$


 * $$\forall n \in \mathbb{N^*} $$


 * $$\left[ \frac{\left[\frac{\left(n-1\right)!+1}{n}\right]}{\frac{\left(n-1\right)!+1}{n}}\right]-\left[\frac{1}{n}\right]=0 \Leftrightarrow n \notin \mathbb{P}$$

Therefore the following relation becomes true :


 * $$\forall n \in \mathbb{N^*} $$


 * $$\left[ \frac{\left[\frac{\left(n-1\right)!+1}{n}\right]}{\frac{\left(n-1\right)!+1}{n}}\right]-\left[\frac{1}{n}\right]=

1-\left[\frac{\left[ {\frac{\left(n!\right)^2}{n^3}}\right]}{\frac{\left(n!\right)^2}{n^3}}\right] $$

Let's choose one of the formulas that are indicated in the first section :


 * $$P_n = \sum_{i=1}^{2^{2^{n}}

}\left(\left[\frac {1+ \sum_{m=1}^{i}{\left( 1-\left[{\frac{\left[{\frac{\left(m!\right)^2}{m^3}}\right]}{\frac{\left(m!\right)^2}{m^3}}}\right]\right)}}{n+1}\right]\times{\left[\frac{n+1}{1+ \sum_{m=1}^{i}{\left( 1-\left[{\frac{\left[{\frac{\left(m!\right)^2}{m^3}}\right]}{\frac{\left(m!\right)^2}{m^3}}}\right]\right)}}\right]}\times{i}\times{\left({1-\left[{\frac{\left[(\frac{\left(i!\right)^2}{i^3}\right]}{\frac{\left(i!\right)^2}{i^3}}}\right]}\right)}\right) $$

let's replace

$$ 1-\left[\frac{\left[ {\frac{\left(m!\right)^2}{m^3}}\right]}{\frac{\left(m!\right)^2}{m^3}}\right] by \left[ \frac{\left[\frac{\left(m-1\right)!+1}{m}\right]}{\frac{\left(m-1\right)!+1}{m}}\right]-\left[\frac{1}{m}\right] $$

and

$$ 1-\left[\frac{\left[ {\frac{\left(i!\right)^2}{i^3}}\right]}{\frac{\left(i!\right)^2}{i^3}}\right] by \left[ \frac{\left[\frac{\left(i-1\right)!+1}{i}\right]}{\frac{\left(i-1\right)!+1}{i}}\right]-\left[\frac{1}{i}\right] $$

Therefore an equivalent expression is :


 * $$P_n = \sum_{i=1}^{2^{2^{n}}}{\left(\left[ \frac{1+\sum_{m=1}^i{\left(\left[\frac{\left[\frac{\left(m-1\right)!+1}{m}\right]}{\frac{\left(m-1\right)!+1}{m}}\right]-\left[\frac{1}{m}\right]\right)}}{n+1} \right]\times \left[ \frac{n+1}{1+\sum_{m=1}^i{\left(\left[\frac{\left[\frac{\left(m-1\right)!+1}{m}\right]}{\frac{\left(m-1\right)!+1}{m}}\right]-\left[\frac{1}{m}\right]\right)}} \right]\times i \times \left( \left[\frac{\left[\frac{\left(i-1\right)!+1}{i}\right]}{\frac{\left(i-1\right)!+1}{i}}\right]-\left[\frac{1}{i}\right]\right) \right) }$$

Function &Omega; according to Lhermite's models

 * $$\Omega\left(n\right)=\sum_{j=1}^n\left({\sum_{i=1}^{n}{\left({{\left[\frac{\left[\frac{n}{i^j}\right]}{\left(\frac{n}{i^j}\right)}\right]}\times\left(1-\left[\frac{\left[\frac{\left(i!\right)^2}{i^3}\right]}{\frac{\left(i!\right)^2}{i^3}}\right]\right)}\right)}}\right)$$

Liouville's function and Lhermite's models

 * $$\lambda\left(n\right)=\left(-1\right)^{\left(\sum_{j=1}^n\left({\sum_{i=1}^{n}{\left({{\left[\frac{\left[\frac{n}{i^j}\right]}{\left(\frac{n}{i^j}\right)}\right]}\times\left(1-\left[\frac{\left[\frac{\left(i!\right)^2}{i^3}\right]}{\frac{\left(i!\right)^2}{i^3}}\right]\right)}\right)}}\right)\right)}$$

Three Arrows or Jonatan's Arrows
There are three possibilities :$$ a > b $$ or $$ b < a  $$ or $$ a = b $$. In the same way, there are three possibilities : $$ V_i > n $$ or $$ V_i < n$$ or $$ V_i = n $$

with