Physics equations/06-Uniform Circular Motion and Gravitation/Q:friction/More practice

{A merry-go-round has an angular frequency, $$\omega$$, equal to 0.174 rad/sec. How many minutes does it take to complete 8.5 revolutions? -a) 3.87 minutes. -b) 4.45 minutes. +c) 5.12 minutes. -d) 5.88 minutes. -e) 6.77 minutes.
 * type="" }

{A merry-go round has a period of 0.34 minutes. What is the centripetal force on a 89.6 kg person who is standing 2.25 meters from the center? -a) 16.6 newtons. +b) 19.1 newtons. -c) 22 newtons. -d) 25.3 newtons. -e) 29.1 newtons.
 * type="" }

{A merry-go round has a period of 0.34 minutes. What is the minimum coefficient of static friction that would allow a 89.6 kg person to stand2.25 meters from the center, without grabbing something? -a) 0.019 +b) 0.022 -c) 0.025 -d) 0.029 -e) 0.033
 * type="" }

{What is the gravitational acceleration on a plant that is 2.67 times more massive than Earth, and a radius that is 1.74 times greater than Earths? -a) 5.7 m/s2 -b) 6.5 m/s2 -c) 7.5 m/s2 +d) 8.6 m/s2 -e) 9.9 m/s2
 * type="" }

{What is the gravitational acceleration on a plant that is 1.95 times more dense than Earth, and a radius that is 2.12 times greater than Earth's? +a) 40.5 m/s2 -b) 46.6 m/s2 -c) 53.6 m/s2 -d) 61.6 m/s2 -e) 70.9 m/s2
 * type="" }

../Testbank/