Power Generation/Diesel Power/Part4

If heat produced by _X kg of oil = Y KCal   (where 1kWh = 860 KCal)

Then we can derive the overal power plant efficiency as:

$${\eta}_{overall} = \frac{860KCal}{Y KCal} \times 100$$ (in %) ... Equation 4.1

Then the engine efficiency becomes:

$${\eta}_{engine} = \frac{\eta_overall}{\eta_alternator} \times 100$$(in %) ... Equation 4.2

Where:_ $${\eta}_{alternator}$$ is specified by manufacturer