Theory of relativity/Kerr–Newman metric

The spacetime metric is, in Boyer-Lindquist coordinates,



ds^2 = \frac{\Delta^2}{\rho^2} (dct - a\, \sin ^2\theta \, d\phi)^2 - \frac{\sin ^2\theta}{\rho^2} [ (r^2 + a^2) d\phi - a\, dct]^2 - \frac{\rho^2}{\Delta^2} dr^2 - \rho^2 d\theta^2 $$

where


 * $$\Delta^2 \equiv a^2 +r^2\alpha $$


 * $$\alpha = 1 - \frac{2GM}{rc^2} + \frac{e^2}{r^2}  $$


 * $$\rho ^2 \equiv r^2 + a^2\cos^2\theta  $$


 * $$a \equiv \frac{J}{Mc} $$


 * $$e \equiv \frac{\sqrt{k_{e}G}}{c^2}q$$

This represents the exact solution to General relativity/Einstein equations for the stress-energy tensor for an electromagnetic field from a charged rotating black hole. Defining three more functions of the coordinates
 * $$\Sigma ^2 \equiv \sqrt{\left( r^2 + a^2 \right)^2 -a^2 \Delta ^2 \sin ^2 \theta}$$
 * $$\varpi \equiv \frac{\Sigma ^2}{\rho}\sin \theta$$
 * $$\omega \equiv a\frac{\left( r^2 +a^2 -\Delta ^2 \right)}{\Sigma ^4}c$$

The solution can now be written
 * $$ds^2 =\left( \frac{\Delta ^2 -a^2 \sin ^2 \theta}{\rho ^2} \right)dct^2 +2\frac{\omega}{c}\varpi ^2 dctd\phi -\varpi ^2 d\phi ^2 -\frac{\rho ^2}{\Delta ^2}dr^2 -\rho ^2 d\theta ^2 $$

$$ds$$ is an invariant line element, a measure of spacetime displacement between neighboring events. The displacement four vector between those events is $$dx^\mu $$, and being a four-vector, would yield an invariant scalar for the inner product of it with itself using the metric tensor $$g_{\mu \nu}$$ as a spacetime inner product operator as $$g_{\mu \nu}dx^{\mu}dx^{\nu}$$. We call that invariant scalar $$ds^2$$.
 * $$ds^2 = g_{\mu \nu}dx^{\mu}dx^{\nu}$$

So though technically it is the set of elements$$\left[ g_{\mu \nu} \right]$$ that is the metric tensor, since its elements can be directly read off of this line element as the coefficients of the coordinate differentials, in jargon $$ds^2$$ is often referred to as just "the metric". In the case that the charge $$q$$ is zero it becomes an exact vacuum solution to Einstein's field equations and is called just "the Kerr solution".

Gravitational Red Shift Factor
The solution
 * $$ds^2 =\left( \frac{\Delta ^2 -a^2 \sin ^2 \theta}{\rho ^2} \right)dct^2 +2\frac{\omega}{c}\varpi ^2 dctd\phi -\varpi ^2 d\phi ^2 -\frac{\rho ^2}{\Delta ^2}dr^2 -\rho ^2 d\theta ^2 $$

may also be written as
 * $$ds^2 =R^2 dct^2 -\varpi ^2 \left( d\phi -\frac{\omega}{c}dct \right)^2 -\frac{\rho ^2}{\Delta ^2}dr^2 -\rho ^2 d\theta ^2 $$

where
 * $$R \equiv \sqrt{\frac{\Delta ^2 -a^2 \sin ^2 \theta}{\rho ^2}+\frac{\omega ^2}{c^2}\varpi ^2}$$

Lets say something neutral is equatorially orbiting in this spacetime with an angular velocity of $$\omega $$, then in using the solution in describing its path through spacetime, or world line, the $$\left( d\phi -\frac{\omega}{c}dct \right)$$ term vanishes and it is said to be "locally nonrotating". If it emits according to its local free fall frame a frequency $$f_{0}$$, then the frequency received by a remote observer $$f'$$ will be red shifted by
 * $$f'=Rf_{0}$$

Mathematical Surfaces
There are three important mathematical surfaces for this line element, the static limit and the inner and outer event horizons. The static limit is the outermost place something can be outside the outer horizon with a zero angular velocity. It is
 * $$r_s = \frac{GM}{c^2}+\sqrt{\left(\frac{GM}{c^2}\right)^2 - a^2 \cos^2 \theta -e^2}$$

The event horizons are coordinate singularities in the metric where $$\Delta = 0$$.

The outer event horizon is at
 * $$r_{+} = \frac{GM}{c^2}+\sqrt{\left(\frac{GM}{c^2}\right)^2 - a^2 -e^2}$$

and the inner horizon is at
 * $$r_{-} = \frac{GM}{c^2}-\sqrt{\left(\frac{GM}{c^2}\right)^2 - a^2 -e^2}$$

An external observer can never see an event at which something crosses into the outer horizon. A remote observer reckoning with these coordinates will reckon that it takes an infinite time for something infalling to reach the outer horizon even though it takes a finite proper time till the event according to what fell in.

Kerr-Newman Equatorial Geodesic Motion
The exact equations of equatorial geodesic motion for a neutral test mass in a charged and rotating black hole's spacetime are
 * $$\frac{dt}{d\tau}=\frac{\gamma \left(r^2 +a^2 +2a^2 \frac{GM}{rc^2}-a^2 \frac{e^2}{r^2}\right)-\frac{al_{z}}{c} \left(\frac{2GM}{rc^2}-\frac{e^2}{r^2}\right)}{r^2 -\frac{2GMr}{c^2} + a^2 +e^2}$$
 * $$\frac{d\phi}{d\tau}=\frac{\frac{l_z}{c} \left(1-\frac{2GM}{rc^2}+\frac{e^2}{r^2}\right)+\gamma a\left(\frac{2GM}{rc^2 }-\frac{e^2}{r^2}\right)}{r^2 -\frac{2GMr}{c^2}+ a^2 +e^2}c$$
 * $$\frac{1}{2}\left(\frac{dr}{d\tau}\right)^2 +V_{eff} =0$$
 * $$V_{eff} = -\frac{GM}{r}+\frac{e^2 c^2 }{2r^2}+\frac{1}{2}\frac{l_z ^2}{r^2} +\frac{1}{2}\left(1-\gamma ^2\right)c^2 \left(1+\frac{a^2}{r^2}\right)-\left(\frac{GM}{r^3 c^2 }-\frac{e^2}{2r^4}\right)\left(\frac{l_z}{c} -a\gamma \right)^2 c^2 $$

where $$\gamma$$ is the conserved energy parameter, the energy per $$mc^2 $$ of the test mass and $$l_z$$ is the conserved angular momentum per mass $$m$$ for the test mass.

Kerr-Newman Polar Geodesic Motion
The exact equations of polar geodesic motion for a neutral test mass in a charged and rotating black hole's spacetime are
 * $$\frac{dt}{d\tau }=\gamma \left(\frac{a^2 +r^2}{a^2 +e^2 +r^2 -\frac{2GMr}{c^2}}\right)$$
 * $$\frac{1}{2}\left(\frac{dr}{d\tau}\right)^2 - \frac{\frac{GM}{rc^2}-\frac{e^2}{2r^2}}{1+\frac{a^2}{r^2}}c^2 = \frac{\gamma ^2 -1}{2}c^2 $$

where $$\gamma$$ is the conserved energy parameter, the energy per $$mc^2 $$ of the test mass.

Wormhole Structure
Above we see a Penrose diagram representing a coordinate extension (1) for a charged or rotating black hole. The same way as mapping Schwarzschild coordinates onto Kruskal-Szekeres coordinate reveals two separate external regions for the Schwarzschild black hole, such a mapping done for a charged or rotating hole reveals an even more multiply connected region for charged and rotating black holes. Lets say region I represents our external region outside a charged black hole. In the same way that the other external region is inaccesible as the wormhole connection is not transversible, external region II is also not accessible from region I. The difference is that there are other external regions VII and VIII which are ideed accesible from region I by transversible paths at least one way. One should expect this as the radial movement case of geodesic motion for a neutral test particle written above leads back out of the hole without intersecting the physical singularity at $$r=0, \theta = \frac{\pi }{2}$$.