User:Eas4200c.f08.blue.a/Lecture 38

resulting for the consequences of the first method,



$$\tilde q_{j6}=\tilde q_{2j}-\tilde q_{j5}- \tilde q_{j8}+q(j)$$

then if the $$\tilde q_{6j}$$ is reversed

then

$$-\tilde q_{j6}=\tilde q_{2j}-\tilde q_{j5}- \tilde q_{j8}+q(j)$$

The question was raised that if one stringer was isolated if the system could still be solved.

this is not true because when one stringer is isolated it would yield that the q of the actual stringer is zero which is known not to be true.

$$\tilde q_{j6}=\tilde q_{2j}-\tilde q_{j5}- \tilde q_{j8}+q(j)$$ which would yeild $$0=0+0+0+q(j)$$ and q(j) is a number that is non zero $$q(j) \neq 0$$ so this yields that the system is unsolvable whenever a stringer is isolated.