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$$ \sum_{j=2}^{5} C_{j} j(j-1) x^{^{j-2}}=\sum_{j=0}^{3} C_{j+2} (j+2)(j+1) x^{^{j}} \!$$ Egm4313.s12.team1.silvestri 19:31, 8 February 2012 (UTC)