User:Egm6341.s10.Team4.roni/HW6/6.4

= Problem 4: Matrix Inversion for Hermite - Simpson Algorithm =

Given
Matrix A [[media:Egm6341.s10.mtg35.djvu|35-3]], which is:


 * {| style="width:100%" border="0" align="left"

$$
 * $$\displaystyle
 * $$\displaystyle

1 & 0 & 0 & 0 \\ 0 & 1 & 0 & 0\\ 1 & 1 & 1 & 1\\ 0 & 1 & 2 & 3 \end{bmatrix}
 * $$\displaystyle A= \begin{bmatrix}

$$
 * style= |
 * }
 * }

Show
That the Inversion of this Matrix A Gives the following Matrix: on slide [[media:Egm6341.s10.mtg35.djvu|35-4]]

$$\displaystyle $$

$$\displaystyle Inv( A ) = \begin{bmatrix} 1 & 0 & 0 & 0 \\ 0 & 1 & 0 & 0\\ -3 & -2 & 3 & -1\\ 2 & 1 & -2 & 1 \end{bmatrix}

$$

Solution
Using MatLab:

 Matlab Code: 

Giving Result,

A_Inv =

1    0     0     0     0     1     0     0    -3    -2     3    -1     2     1    -2     1

Author
Solved and typed by - --Egm6341.s10.Team4.roni 01:15, 7 April 2010 (UTC) Reviewed by -