User:Eml4500.f08.delta 6.ramirez/nodeequilibrium

Verification of Equilibrium of element 1:
Note: The reactions for node 1 were calculated to be

F1(1) = -4.4278

F2(1) = -2.5622

F3(1) = 4.4278

F4(1) = 2.5622



Note: Negative values signify that the direction of the forces in element 1 were assumed to be in the wrong direction.

Redrawing the free body diagram with all positive forces shows more clearly how the resultant forces P1 and P2 cancel each other out.

Now,

F1(1) = 4.4278

F2(1) = 2.5622

F3(1) = 4.4278

F4(1) = 2.5622



Determining Resultants:

P­­­1= [(f1(1))2 + (f2(1))2]1/2= [(4.4278)2+ (2.5622)2]1/2= 5.12 

P­­­2= [ (f3(1))2 + (f4(1))2]1/2= [(4.4278)2+ (2.5622)2]1/2= 5.12

Note: P1 = P2, thus element 1 is in equilibrium.