User talk:Egm4313.s12.team1.silvestri

First edit. Here's to seeing what will happen.

playing with equations

First, we identify the property of periodic functions, as shown on p9-2 of the notes, equation (1)


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$$\displaystyle{f(x+np)=f(x)}$$ (1.0)
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So for $$ \cos n \omega x $$, the following determines the smallest period.


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$$\displaystyle{\cos (n\omega x)}$$ (1.1) We then add $$ 2 \pi $$ to see a final expression that will be equal to $$\displaystyle{f(x+np)=f(x)} $$
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$$\displaystyle{\cos (n\omega x + 2 \pi)}$$ (1.2)
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We then pull out a term that leaves an x plus a number (our period) inside the trigonometric function, cosine.
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$$\displaystyle{\cos[n\omega ( x + \frac{2 \pi)}{n \omega}]}$$ (1.3) This means the smallest period is $$ frac{2 \pi}{n \omega} $$.
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For $$ \sin n \omega x $$, the following determines the smallest period.


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$$\displaystyle{\sin (n\omega x)}$$ (1.4) We then add $$ 2 \pi $$ to see a final expression that will be equal to $$\displaystyle{f(x+np)=f(x)} $$
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$$\displaystyle{\sin (n\omega x + 2 \pi)}$$ (1.5)
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We then pull out a term that leaves an x plus a number (our period) inside the trigonometric function, cosine.
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$$\displaystyle{\sin[n\omega ( x + \frac{2 \pi)}{n \omega}]}$$ (1.6) This means the smallest period is $$ frac{2 \pi}{n \omega} $$, just as for its cosine equivalent.
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Egm4313.s12.team1.silvestri 20:09, 25 January 2012 (UTC)

What is the copyright of File:Report1.1.jpg?
Alpha = .5

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MaintenanceBot (discuss • contribs) 03:41, 11 November 2013 (UTC)